Lua编程示例(六): C语言调用Lua函数

2019-10-28 18:48:22 来源:易采站长站 作者:于丽

C++端:

#include "stdafx.h"

lua_State *L;
void load_lua(lua_State **L,char *filename){
 *L=luaL_newstate();
 luaL_openlibs(*L);
 if(luaL_loadfile(*L,filename) || lua_pcall(*L,0,0,0)){
 luaL_error(*L,"load file error! %s",lua_tostring(*L,-1));
 }
}
int _tmain(int argc, _TCHAR* argv[])
{
 load_lua(&L,"raw.lua"); //此处若直接传入L会出错
 lua_getglobal(L,"gettable");
 if(lua_pcall(L,0,1,0) !=0){
 luaL_error(L,"pcall wrong %s",lua_tostring(L,-1));
 }
 luaL_checktype(L,1,LUA_TTABLE);
 int n=lua_objlen(L,1);
 printf("n = %dn",n);
 lua_pushstring(L,"ee");
 lua_rawseti(L,1,5); //t[n]=v,n为第三个参数,v是栈顶元素
 n=lua_objlen(L,1);
 printf("n = %dn",n);
 int i;
 for(i=1;i<=n;i++){
 lua_rawgeti(L,1,i);
 printf("%sn",lua_tostring(L,-1));
 }
 return 0;
}

lua脚本:

 

function gettable() 
  tb={ "aa","bb","cc","dd"} 
  return tb 
end 

运行输出的结果为:

n = 4 
n = 5 
aa 
bb 
cc 
dd 
ee

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